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130442013011 = 415793137209
BaseRepresentation
bin111100101111011110…
…0110010100101010011
3110110200201122211111002
41321132330302211103
54114121123404021
6135531345012215
712265321550012
oct1713674624523
9413621584432
10130442013011
1150358130042
122134492406b
13c3ba635cab
146456088a79
1535d6a7550b
hex1e5ef32953

130442013011 has 4 divisors (see below), whose sum is σ = 130445191800. Its totient is φ = 130438834224.

The previous prime is 130442012999. The next prime is 130442013017. The reversal of 130442013011 is 110310244031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130442013011 - 214 = 130441996627 is a prime.

It is a super-2 number, since 2×1304420130112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130442013017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1527026 + ... + 1610183.

It is an arithmetic number, because the mean of its divisors is an integer number (32611297950).

Almost surely, 2130442013011 is an apocalyptic number.

130442013011 is a deficient number, since it is larger than the sum of its proper divisors (3178789).

130442013011 is an equidigital number, since it uses as much as digits as its factorization.

130442013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3178788.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 130442013011 its reverse (110310244031), we get a palindrome (240752257042).

The spelling of 130442013011 in words is "one hundred thirty billion, four hundred forty-two million, thirteen thousand, eleven".

Divisors: 1 41579 3137209 130442013011