13044203121 has 4 divisors (see below), whose sum is σ = 17392270832. Its totient is φ = 8696135412.

The previous prime is 13044203099. The next prime is 13044203149. The reversal of 13044203121 is 12130244031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12130244031 = 3 ⋅4043414677.

It is not a de Polignac number, because 13044203121 - 2⁹ = 13044202609 is a prime.

It is a super-2 number, since 2×13044203121² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044203321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2174033851 + ... + 2174033856.

It is an arithmetic number, because the mean of its divisors is an integer number (4348067708).

Almost surely, 2^13044203121 is an apocalyptic number.

It is an amenable number.

13044203121 is a deficient number, since it is larger than the sum of its proper divisors (4348067711).

13044203121 is an equidigital number, since it uses as much as digits as its factorization.

13044203121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4348067710.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13044203121 its reverse (12130244031), we get a palindrome (25174447152).

The spelling of 13044203121 in words is "thirteen billion, forty-four million, two hundred three thousand, one hundred twenty-one".