Base | Representation |
---|---|
bin | 1011110111010001100101… |
… | …0111110010011000000011 |
3 | 1201012000110121101122221220 |
4 | 2331310121113302120003 |
5 | 3202204101241002003 |
6 | 43424235230050123 |
7 | 2514262313666532 |
oct | 275643127623003 |
9 | 51160417348856 |
10 | 13044241344003 |
11 | 417a0391a3311 |
12 | 156808a049943 |
13 | 7380b3660b8c |
14 | 3314b7a0c319 |
15 | 17949d6b8353 |
hex | bdd195f2603 |
13044241344003 has 4 divisors (see below), whose sum is σ = 17392321792008. Its totient is φ = 8696160896000.
The previous prime is 13044241343983. The next prime is 13044241344007. The reversal of 13044241344003 is 30044314244031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13044241344003 - 232 = 13039946376707 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13044241344007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2174040223998 + ... + 2174040224003.
It is an arithmetic number, because the mean of its divisors is an integer number (4348080448002).
Almost surely, 213044241344003 is an apocalyptic number.
13044241344003 is a deficient number, since it is larger than the sum of its proper divisors (4348080448005).
13044241344003 is an equidigital number, since it uses as much as digits as its factorization.
13044241344003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4348080448004.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13044241344003 its reverse (30044314244031), we get a palindrome (43088555588034).
The spelling of 13044241344003 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, three hundred forty-four thousand, three".
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