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130443031014011 = 373525487324703
BaseRepresentation
bin11101101010001100100010…
…100001101110101001111011
3122002212020021010000122211022
4131222030202201232221323
5114044134311414422021
61141232411242053055
736322124624200022
oct3552144241565173
9562766233018738
10130443031014011
1138621640401321
12127688971aa18b
1357a2956bc89a1
14242d6952c98b9
1510131c8ae71ab
hex76a32286ea7b

130443031014011 has 4 divisors (see below), whose sum is σ = 133968518338752. Its totient is φ = 126917543689272.

The previous prime is 130443031014001. The next prime is 130443031014017. The reversal of 130443031014011 is 110410130344031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130443031014011 - 26 = 130443031013947 is a prime.

It is a super-2 number, since 2×1304430310140112 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130443031014017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1762743662315 + ... + 1762743662388.

It is an arithmetic number, because the mean of its divisors is an integer number (33492129584688).

Almost surely, 2130443031014011 is an apocalyptic number.

130443031014011 is a deficient number, since it is larger than the sum of its proper divisors (3525487324741).

130443031014011 is an equidigital number, since it uses as much as digits as its factorization.

130443031014011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3525487324740.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 130443031014011 its reverse (110410130344031), we get a palindrome (240853161358042).

The spelling of 130443031014011 in words is "one hundred thirty trillion, four hundred forty-three billion, thirty-one million, fourteen thousand, eleven".

Divisors: 1 37 3525487324703 130443031014011