13044400132241 has 4 divisors (see below), whose sum is σ = 13048678390500. Its totient is φ = 13040121873984.

The previous prime is 13044400132217. The next prime is 13044400132243. The reversal of 13044400132241 is 14223100444031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 404490912016 + 12639909220225 = 635996^2 + 3555265^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13044400132241 is a prime.

It is a super-3 number, since 3×13044400132241³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13044400132243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2139124556 + ... + 2139130653.

It is an arithmetic number, because the mean of its divisors is an integer number (3262169597625).

Almost surely, 2^{13044400132241} is an apocalyptic number.

It is an amenable number.

13044400132241 is a deficient number, since it is larger than the sum of its proper divisors (4278258259).

13044400132241 is an equidigital number, since it uses as much as digits as its factorization.

13044400132241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4278258258.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 13044400132241 its reverse (14223100444031), we get a palindrome (27267500576272).

The spelling of 13044400132241 in words is "thirteen trillion, forty-four billion, four hundred million, one hundred thirty-two thousand, two hundred forty-one".