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1304513522113 = 1968658606427
BaseRepresentation
bin10010111110111011000…
…100001010100111000001
311121201011210100010120211
4102332323010022213001
5132333120430201423
62435141340034121
7163151026661104
oct22767304124701
94551153303524
101304513522113
1146327196915a
121909a6b32941
1396027226999
14471d2bb473b
1523e002d510d
hex12fbb10a9c1

1304513522113 has 4 divisors (see below), whose sum is σ = 1373172128560. Its totient is φ = 1235854915668.

The previous prime is 1304513522063. The next prime is 1304513522131. The reversal of 1304513522113 is 3112253154031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304513522113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304513522173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34329303195 + ... + 34329303232.

It is an arithmetic number, because the mean of its divisors is an integer number (343293032140).

Almost surely, 21304513522113 is an apocalyptic number.

It is an amenable number.

1304513522113 is a deficient number, since it is larger than the sum of its proper divisors (68658606447).

1304513522113 is an equidigital number, since it uses as much as digits as its factorization.

1304513522113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68658606446.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1304513522113 its reverse (3112253154031), we get a palindrome (4416766676144).

The spelling of 1304513522113 in words is "one trillion, three hundred four billion, five hundred thirteen million, five hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 19 68658606427 1304513522113