Base | Representation |
---|---|
bin | 111100110000011010… |
… | …1001000001000011011 |
3 | 110110202221000111211120 |
4 | 1321200311020020123 |
5 | 4114202212333210 |
6 | 135534433100323 |
7 | 12266153643354 |
oct | 1714065101033 |
9 | 413687014746 |
10 | 130473558555 |
11 | 50373a1673a |
12 | 213533b76a3 |
13 | c3c402c5b2 |
14 | 645a33ad2b |
15 | 35d9707270 |
hex | 1e60d4821b |
130473558555 has 16 divisors (see below), whose sum is σ = 211272848640. Its totient is φ = 68747512928.
The previous prime is 130473558547. The next prime is 130473558559. The reversal of 130473558555 is 555855374031.
It is a cyclic number.
It is not a de Polignac number, because 130473558555 - 23 = 130473558547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130473558498 and 130473558507.
It is not an unprimeable number, because it can be changed into a prime (130473558559) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52397775 + ... + 52400264.
It is an arithmetic number, because the mean of its divisors is an integer number (13204553040).
Almost surely, 2130473558555 is an apocalyptic number.
130473558555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130473558555 is a deficient number, since it is larger than the sum of its proper divisors (80799290085).
130473558555 is a wasteful number, since it uses less digits than its factorization.
130473558555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104798130.
The product of its (nonzero) digits is 6300000, while the sum is 51.
The spelling of 130473558555 in words is "one hundred thirty billion, four hundred seventy-three million, five hundred fifty-eight thousand, five hundred fifty-five".
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