Base | Representation |
---|---|
bin | 11000010011100011… |
… | …01010111010101001 |
3 | 1020200101211200220011 |
4 | 30021301222322221 |
5 | 203211010331143 |
6 | 5554455331521 |
7 | 641235653521 |
oct | 141161527251 |
9 | 36611750804 |
10 | 13048917673 |
11 | 5596856a90 |
12 | 2642080ba1 |
13 | 12cc56b57c |
14 | 8bb060681 |
15 | 5158b5e9d |
hex | 309c6aea9 |
13048917673 has 4 divisors (see below), whose sum is σ = 14235182928. Its totient is φ = 11862652420.
The previous prime is 13048917671. The next prime is 13048917677. The reversal of 13048917673 is 37671984031.
13048917673 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13048917673 - 21 = 13048917671 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13048917671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 593132611 + ... + 593132632.
It is an arithmetic number, because the mean of its divisors is an integer number (3558795732).
Almost surely, 213048917673 is an apocalyptic number.
It is an amenable number.
13048917673 is a deficient number, since it is larger than the sum of its proper divisors (1186265255).
13048917673 is a wasteful number, since it uses less digits than its factorization.
13048917673 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1186265254.
The product of its (nonzero) digits is 762048, while the sum is 49.
The spelling of 13048917673 in words is "thirteen billion, forty-eight million, nine hundred seventeen thousand, six hundred seventy-three".
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