Base | Representation |
---|---|
bin | 10010111111010100001… |
… | …010100101111111111001 |
3 | 11121202021010202000101021 |
4 | 102333110022211333321 |
5 | 132340001231400221 |
6 | 2435251222022441 |
7 | 163164332255662 |
oct | 22772412457771 |
9 | 4552233660337 |
10 | 1304934637561 |
11 | 463468646455 |
12 | 190aa3b77a21 |
13 | 9609354c319 |
14 | 47232ab4369 |
15 | 23e2726a041 |
hex | 12fd42a5ff9 |
1304934637561 has 16 divisors (see below), whose sum is σ = 1399559067648. Its totient is φ = 1212320800000.
The previous prime is 1304934637549. The next prime is 1304934637577. The reversal of 1304934637561 is 1657364394031.
It is a cyclic number.
It is not a de Polignac number, because 1304934637561 - 215 = 1304934604793 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1304934637499 and 1304934637508.
It is not an unprimeable number, because it can be changed into a prime (1304934635561) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1222311 + ... + 2025811.
It is an arithmetic number, because the mean of its divisors is an integer number (87472441728).
Almost surely, 21304934637561 is an apocalyptic number.
It is an amenable number.
1304934637561 is a deficient number, since it is larger than the sum of its proper divisors (94624430087).
1304934637561 is a wasteful number, since it uses less digits than its factorization.
1304934637561 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 804752.
The product of its (nonzero) digits is 4898880, while the sum is 52.
The spelling of 1304934637561 in words is "one trillion, three hundred four billion, nine hundred thirty-four million, six hundred thirty-seven thousand, five hundred sixty-one".
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