Base | Representation |
---|---|
bin | 11000010011101110… |
… | …00100100010001011 |
3 | 1020200111111121210122 |
4 | 30021313010202023 |
5 | 203211341131243 |
6 | 5554545533455 |
7 | 641254001006 |
oct | 141167044213 |
9 | 36614447718 |
10 | 13050333323 |
11 | 5597633645 |
12 | 264264428b |
13 | 12cc945a31 |
14 | 8bb30c53d |
15 | 515a95668 |
hex | 309dc488b |
13050333323 has 4 divisors (see below), whose sum is σ = 13063503168. Its totient is φ = 13037163480.
The previous prime is 13050333311. The next prime is 13050333337. The reversal of 13050333323 is 32333305031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13050333323 - 220 = 13049284747 is a prime.
It is a super-2 number, since 2×130503333232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13050333292 and 13050333301.
It is not an unprimeable number, because it can be changed into a prime (13050333353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6583436 + ... + 6585417.
It is an arithmetic number, because the mean of its divisors is an integer number (3265875792).
Almost surely, 213050333323 is an apocalyptic number.
13050333323 is a deficient number, since it is larger than the sum of its proper divisors (13169845).
13050333323 is an equidigital number, since it uses as much as digits as its factorization.
13050333323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13169844.
The product of its (nonzero) digits is 7290, while the sum is 26.
Adding to 13050333323 its reverse (32333305031), we get a palindrome (45383638354).
The spelling of 13050333323 in words is "thirteen billion, fifty million, three hundred thirty-three thousand, three hundred twenty-three".
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