1305100113 has 4 divisors (see below), whose sum is σ = 1740133488. Its totient is φ = 870066740.

The previous prime is 1305100091. The next prime is 1305100123. The reversal of 1305100113 is 3110015031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1305100113 - 2⁸ = 1305099857 is a prime.

It is a super-2 number, since 2×1305100113² = 3406572609905225538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1305100092 and 1305100101.

It is not an unprimeable number, because it can be changed into a prime (1305100123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217516683 + ... + 217516688.

It is an arithmetic number, because the mean of its divisors is an integer number (435033372).

Almost surely, 2^1305100113 is an apocalyptic number.

It is an amenable number.

1305100113 is a deficient number, since it is larger than the sum of its proper divisors (435033375).

1305100113 is an equidigital number, since it uses as much as digits as its factorization.

1305100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 435033374.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 1305100113 is about 36126.1693651569. The cubic root of 1305100113 is about 1092.8182583896.

Adding to 1305100113 its reverse (3110015031), we get a palindrome (4415115144).

The spelling of 1305100113 in words is "one billion, three hundred five million, one hundred thousand, one hundred thirteen".