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13053115 = 52610623
BaseRepresentation
bin110001110010…
…110010111011
3220120011111201
4301302302323
511320144430
61143435031
7215643505
oct61626273
926504451
1013053115
117405aa9
124455a77
13292044a
141a3ad75
15122c8ca
hexc72cbb

13053115 has 4 divisors (see below), whose sum is σ = 15663744. Its totient is φ = 10442488.

The previous prime is 13053097. The next prime is 13053143. The reversal of 13053115 is 51135031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13053115 - 25 = 13053083 is a prime.

It is a super-2 number, since 2×130531152 = 340767622406450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13053092 and 13053101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1305307 + ... + 1305316.

It is an arithmetic number, because the mean of its divisors is an integer number (3915936).

Almost surely, 213053115 is an apocalyptic number.

13053115 is a deficient number, since it is larger than the sum of its proper divisors (2610629).

13053115 is an equidigital number, since it uses as much as digits as its factorization.

13053115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2610628.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 13053115 is about 3612.9094923621. The cubic root of 13053115 is about 235.4532673230.

Adding to 13053115 its reverse (51135031), we get a palindrome (64188146).

The spelling of 13053115 in words is "thirteen million, fifty-three thousand, one hundred fifteen".

Divisors: 1 5 2610623 13053115