Base | Representation |
---|---|
bin | 11000010100000110… |
… | …01111001000000001 |
3 | 1020200201111122102211 |
4 | 30022003033020001 |
5 | 203213200204213 |
6 | 5555142142121 |
7 | 641323052500 |
oct | 141203171001 |
9 | 36621448384 |
10 | 13053522433 |
11 | 5599411676 |
12 | 2643721941 |
13 | 13004c1493 |
14 | 8bb8dc837 |
15 | 515ec553d |
hex | 30a0cf201 |
13053522433 has 6 divisors (see below), whose sum is σ = 15184709826. Its totient is φ = 11188733472.
The previous prime is 13053522421. The next prime is 13053522463. The reversal of 13053522433 is 33422535031.
It can be written as a sum of positive squares in only one way, i.e., 12644552704 + 408969729 = 112448^2 + 20223^2 .
It is not a de Polignac number, because 13053522433 - 233 = 4463587841 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13053522395 and 13053522404.
It is not an unprimeable number, because it can be changed into a prime (13053522463) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 133199160 + ... + 133199257.
It is an arithmetic number, because the mean of its divisors is an integer number (2530784971).
Almost surely, 213053522433 is an apocalyptic number.
It is an amenable number.
13053522433 is a deficient number, since it is larger than the sum of its proper divisors (2131187393).
13053522433 is an equidigital number, since it uses as much as digits as its factorization.
13053522433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266398431 (or 266398424 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 31.
The spelling of 13053522433 in words is "thirteen billion, fifty-three million, five hundred twenty-two thousand, four hundred thirty-three".
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