Base | Representation |
---|---|
bin | 10010111111101101001… |
… | …011111100001110001011 |
3 | 11121210100101122020011220 |
4 | 102333231023330032023 |
5 | 132341331212434011 |
6 | 2435401015253123 |
7 | 163210620335535 |
oct | 22775513741613 |
9 | 4553311566156 |
10 | 1305354421131 |
11 | 4636635a4022 |
12 | 190ba067a1a3 |
13 | 9612c4c9677 |
14 | 47272748855 |
15 | 23e4e03a506 |
hex | 12fed2fc38b |
1305354421131 has 16 divisors (see below), whose sum is σ = 1751143802880. Its totient is φ = 864908779680.
The previous prime is 1305354421117. The next prime is 1305354421159. The reversal of 1305354421131 is 1311244535031.
It is not a de Polignac number, because 1305354421131 - 214 = 1305354404747 is a prime.
It is a super-2 number, since 2×13053544211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1305354421092 and 1305354421101.
It is not an unprimeable number, because it can be changed into a prime (1305354421171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 370816 + ... + 1657773.
It is an arithmetic number, because the mean of its divisors is an integer number (109446487680).
Almost surely, 21305354421131 is an apocalyptic number.
1305354421131 is a deficient number, since it is larger than the sum of its proper divisors (445789381749).
1305354421131 is a wasteful number, since it uses less digits than its factorization.
1305354421131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2029906.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 1305354421131 its reverse (1311244535031), we get a palindrome (2616598956162).
The spelling of 1305354421131 in words is "one trillion, three hundred five billion, three hundred fifty-four million, four hundred twenty-one thousand, one hundred thirty-one".
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