Base | Representation |
---|---|
bin | 10010111111101111111… |
… | …101110001110010100011 |
3 | 11121210110122100201021222 |
4 | 102333233331301302203 |
5 | 132341430131240120 |
6 | 2435405402405255 |
7 | 163212024521651 |
oct | 22775775616243 |
9 | 4553418321258 |
10 | 1305401040035 |
11 | 463687945544 |
12 | 190bb420082b |
13 | 9613906cb11 |
14 | 47278a01dd1 |
15 | 23e53198525 |
hex | 12feff71ca3 |
1305401040035 has 8 divisors (see below), whose sum is σ = 1566995035200. Its totient is φ = 1043978307264.
The previous prime is 1305401040023. The next prime is 1305401040077. The reversal of 1305401040035 is 5300401045031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1305401040035 - 216 = 1305400974499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1305401039986 and 1305401040013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42798827 + ... + 42829316.
It is an arithmetic number, because the mean of its divisors is an integer number (195874379400).
Almost surely, 21305401040035 is an apocalyptic number.
1305401040035 is a deficient number, since it is larger than the sum of its proper divisors (261593995165).
1305401040035 is an equidigital number, since it uses as much as digits as its factorization.
1305401040035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85631197.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 1305401040035 its reverse (5300401045031), we get a palindrome (6605802085066).
The spelling of 1305401040035 in words is "one trillion, three hundred five billion, four hundred one million, forty thousand, thirty-five".
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