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130543113 = 343514371
BaseRepresentation
bin1111100011111…
…10111000001001
3100002122021111010
413301332320021
5231404334423
620541554133
73143412111
oct761767011
9302567433
10130543113
1167762a78
1237875949
1321078a5c
14134a2041
15b6d9693
hex7c7ee09

130543113 has 4 divisors (see below), whose sum is σ = 174057488. Its totient is φ = 87028740.

The previous prime is 130543109. The next prime is 130543157. The reversal of 130543113 is 311345031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130543113 - 22 = 130543109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130543113.

It is not an unprimeable number, because it can be changed into a prime (130543163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21757183 + ... + 21757188.

It is an arithmetic number, because the mean of its divisors is an integer number (43514372).

Almost surely, 2130543113 is an apocalyptic number.

It is an amenable number.

130543113 is a deficient number, since it is larger than the sum of its proper divisors (43514375).

130543113 is an equidigital number, since it uses as much as digits as its factorization.

130543113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43514374.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 130543113 is about 11425.5465077168. The cubic root of 130543113 is about 507.2841833539.

Adding to 130543113 its reverse (311345031), we get a palindrome (441888144).

The spelling of 130543113 in words is "one hundred thirty million, five hundred forty-three thousand, one hundred thirteen".

Divisors: 1 3 43514371 130543113