Base | Representation |
---|---|
bin | 1011110111110111110100… |
… | …0100110001011000101011 |
3 | 1201012222221211102101111122 |
4 | 2331331331010301120223 |
5 | 3202341111011443103 |
6 | 43433053434445455 |
7 | 2515104531160364 |
oct | 275757504613053 |
9 | 51188854371448 |
10 | 13054504015403 |
11 | 4183425206224 |
12 | 156a072b9388b |
13 | 73905a8a94c6 |
14 | 331bac9c8b6b |
15 | 17989e65eb38 |
hex | bdf7d13162b |
13054504015403 has 4 divisors (see below), whose sum is σ = 13080457304208. Its totient is φ = 13028550726600.
The previous prime is 13054504015387. The next prime is 13054504015439. The reversal of 13054504015403 is 30451040545031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13054504015403 - 24 = 13054504015387 is a prime.
It is a super-2 number, since 2×130545040154032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13054504015603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12976643648 + ... + 12976644653.
It is an arithmetic number, because the mean of its divisors is an integer number (3270114326052).
Almost surely, 213054504015403 is an apocalyptic number.
13054504015403 is a deficient number, since it is larger than the sum of its proper divisors (25953288805).
13054504015403 is an equidigital number, since it uses as much as digits as its factorization.
13054504015403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25953288804.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 13054504015403 in words is "thirteen trillion, fifty-four billion, five hundred four million, fifteen thousand, four hundred three".
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