Base | Representation |
---|---|
bin | 1011110111111101110100… |
… | …1010110010101111000011 |
3 | 1201020011010012001011222011 |
4 | 2331333131022302233003 |
5 | 3202402411222102111 |
6 | 43433521425353351 |
7 | 2515162505444146 |
oct | 275773512625703 |
9 | 51204105034864 |
10 | 13056116206531 |
11 | 4184082254292 |
12 | 156a442a98857 |
13 | 7392568c0258 |
14 | 331cc2b7405d |
15 | 179945e6b021 |
hex | bdfdd2b2bc3 |
13056116206531 has 4 divisors (see below), whose sum is σ = 13056304972464. Its totient is φ = 13055927440600.
The previous prime is 13056116206519. The next prime is 13056116206537. The reversal of 13056116206531 is 13560261165031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13056116206531 - 25 = 13056116206499 is a prime.
It is a super-2 number, since 2×130561162065312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13056116206537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94279180 + ... + 94417561.
It is an arithmetic number, because the mean of its divisors is an integer number (3264076243116).
Almost surely, 213056116206531 is an apocalyptic number.
13056116206531 is a deficient number, since it is larger than the sum of its proper divisors (188765933).
13056116206531 is an equidigital number, since it uses as much as digits as its factorization.
13056116206531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 188765932.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 13056116206531 in words is "thirteen trillion, fifty-six billion, one hundred sixteen million, two hundred six thousand, five hundred thirty-one".
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