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13056623481 = 311395655257
BaseRepresentation
bin11000010100011110…
…00100001101111001
31020200221100012021110
430022033010031321
5203214443422411
65555332430533
7641361316446
oct141217041571
936627305243
1013056623481
1155a013a520
122644778449
131301038b15
148bc0a89cd
155163d92a6
hex30a3c4379

13056623481 has 8 divisors (see below), whose sum is σ = 18991452384. Its totient is φ = 7913105120.

The previous prime is 13056623473. The next prime is 13056623491. The reversal of 13056623481 is 18432665031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13056623481 - 23 = 13056623473 is a prime.

It is a super-2 number, since 2×130566234812 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13056623401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 197827596 + ... + 197827661.

It is an arithmetic number, because the mean of its divisors is an integer number (2373931548).

Almost surely, 213056623481 is an apocalyptic number.

13056623481 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13056623481 is a deficient number, since it is larger than the sum of its proper divisors (5934828903).

13056623481 is a wasteful number, since it uses less digits than its factorization.

13056623481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 395655271.

The product of its (nonzero) digits is 103680, while the sum is 39.

The spelling of 13056623481 in words is "thirteen billion, fifty-six million, six hundred twenty-three thousand, four hundred eighty-one".

Divisors: 1 3 11 33 395655257 1186965771 4352207827 13056623481