13065540462001 has 4 divisors (see below), whose sum is σ = 13286990300400. Its totient is φ = 12844090623604.

The previous prime is 13065540461983. The next prime is 13065540462019. The reversal of 13065540462001 is 10026404556031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13065540461983) and next prime (13065540462019).

It is a cyclic number.

It is not a de Polignac number, because 13065540462001 - 2¹⁵ = 13065540429233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13065540402001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110724919111 + ... + 110724919228.

It is an arithmetic number, because the mean of its divisors is an integer number (3321747575100).

Almost surely, 2^{13065540462001} is an apocalyptic number.

It is an amenable number.

13065540462001 is a deficient number, since it is larger than the sum of its proper divisors (221449838399).

13065540462001 is an equidigital number, since it uses as much as digits as its factorization.

13065540462001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221449838398.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 13065540462001 in words is "thirteen trillion, sixty-five billion, five hundred forty million, four hundred sixty-two thousand, one".