130665411256153 has 4 divisors (see below), whose sum is σ = 130665434341428. Its totient is φ = 130665388170880.

The previous prime is 130665411256111. The next prime is 130665411256189. The reversal of 130665411256153 is 351652114566031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 128390949126729 + 2274462129424 = 11330973^2 + 1508132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130665411256153 is a prime.

It is a super-2 number, since 2×130665411256153² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130665411256097 and 130665411256106.

It is not an unprimeable number, because it can be changed into a prime (130665411256553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3368013 + ... + 16512853.

It is an arithmetic number, because the mean of its divisors is an integer number (32666358585357).

Almost surely, 2^{130665411256153} is an apocalyptic number.

It is an amenable number.

130665411256153 is a deficient number, since it is larger than the sum of its proper divisors (23085275).

130665411256153 is an equidigital number, since it uses as much as digits as its factorization.

130665411256153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23085274.

The product of its (nonzero) digits is 1944000, while the sum is 49.

The spelling of 130665411256153 in words is "one hundred thirty trillion, six hundred sixty-five billion, four hundred eleven million, two hundred fifty-six thousand, one hundred fifty-three".