13068343481 has 4 divisors (see below), whose sum is σ = 13636532352. Its totient is φ = 12500154612.

The previous prime is 13068343429. The next prime is 13068343499. The reversal of 13068343481 is 18434386031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13068343481 - 2⁶ = 13068343417 is a prime.

It is a super-2 number, since 2×13068343481² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13068343181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284094401 + ... + 284094446.

It is an arithmetic number, because the mean of its divisors is an integer number (3409133088).

Almost surely, 2^13068343481 is an apocalyptic number.

It is an amenable number.

13068343481 is a deficient number, since it is larger than the sum of its proper divisors (568188871).

13068343481 is an equidigital number, since it uses as much as digits as its factorization.

13068343481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 568188870.

The product of its (nonzero) digits is 165888, while the sum is 41.

The spelling of 13068343481 in words is "thirteen billion, sixty-eight million, three hundred forty-three thousand, four hundred eighty-one".