1307508314113 has 4 divisors (see below), whose sum is σ = 1307556898560. Its totient is φ = 1307459729668.

The previous prime is 1307508314111. The next prime is 1307508314213. The reversal of 1307508314113 is 3114138057031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1307508314113 - 2¹ = 1307508314111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1307508314111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24251833 + ... + 24305686.

It is an arithmetic number, because the mean of its divisors is an integer number (326889224640).

Almost surely, 2^{1307508314113} is an apocalyptic number.

It is an amenable number.

1307508314113 is a deficient number, since it is larger than the sum of its proper divisors (48584447).

1307508314113 is an equidigital number, since it uses as much as digits as its factorization.

1307508314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48584446.

The product of its (nonzero) digits is 30240, while the sum is 37.

The spelling of 1307508314113 in words is "one trillion, three hundred seven billion, five hundred eight million, three hundred fourteen thousand, one hundred thirteen".