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130778934003 = 3297114964977
BaseRepresentation
bin111100111001100001…
…0000010101011110011
3110111120012122012012100
41321303002002223303
54120313401342003
6140025022231443
712306552411654
oct1716302025363
9414505565170
10130778934003
1150510331843
1221419725583
13c442390023
146488b0d52b
153606428ba3
hex1e73082af3

130778934003 has 12 divisors (see below), whose sum is σ = 189097462008. Its totient is φ = 87096160320.

The previous prime is 130778933993. The next prime is 130778934019. The reversal of 130778934003 is 300439877031.

It is not a de Polignac number, because 130778934003 - 213 = 130778925811 is a prime.

It is a super-2 number, since 2×1307789340032 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130778934003.

It is not an unprimeable number, because it can be changed into a prime (130778934023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7473750 + ... + 7491227.

It is an arithmetic number, because the mean of its divisors is an integer number (15758121834).

Almost surely, 2130778934003 is an apocalyptic number.

130778934003 is a deficient number, since it is larger than the sum of its proper divisors (58318528005).

130778934003 is a wasteful number, since it uses less digits than its factorization.

130778934003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14965954 (or 14965951 counting only the distinct ones).

The product of its (nonzero) digits is 381024, while the sum is 45.

The spelling of 130778934003 in words is "one hundred thirty billion, seven hundred seventy-eight million, nine hundred thirty-four thousand, three".

Divisors: 1 3 9 971 2913 8739 14964977 44894931 134684793 14530992667 43592978001 130778934003