13100004114241 has 4 divisors (see below), whose sum is σ = 14290913579184. Its totient is φ = 11909094649300.

The previous prime is 13100004114173. The next prime is 13100004114259. The reversal of 13100004114241 is 14241140000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100004114241 - 2³⁹ = 12550248300353 is a prime.

It is a super-2 number, since 2×13100004114241² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13100004114541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595454732455 + ... + 595454732476.

It is an arithmetic number, because the mean of its divisors is an integer number (3572728394796).

Almost surely, 2^{13100004114241} is an apocalyptic number.

13100004114241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13100004114241 is a deficient number, since it is larger than the sum of its proper divisors (1190909464943).

13100004114241 is a wasteful number, since it uses less digits than its factorization.

13100004114241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1190909464942.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 13100004114241 its reverse (14241140000131), we get a palindrome (27341144114372).

It can be divided in two parts, 1310000 and 4114241, that added together give a square (5424241 = 2329²).

The spelling of 13100004114241 in words is "thirteen trillion, one hundred billion, four million, one hundred fourteen thousand, two hundred forty-one".