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13100024113 = 113159651127
BaseRepresentation
bin11000011001101001…
…01000000100110001
31020210222000011202021
430030310220010301
5203312101232423
610003522551441
7642426240061
oct141464500461
936728004667
1013100024113
115612693010
122657208581
13130a023477
148c3b653a1
1551a10d95d
hex30cd28131

13100024113 has 16 divisors (see below), whose sum is σ = 15001989120. Its totient is φ = 11329592400.

The previous prime is 13100024053. The next prime is 13100024117. The reversal of 13100024113 is 31142000131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100024113 is a prime.

It is a super-2 number, since 2×131000241132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100024117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 305445 + ... + 345682.

It is an arithmetic number, because the mean of its divisors is an integer number (937624320).

Almost surely, 213100024113 is an apocalyptic number.

It is an amenable number.

13100024113 is a deficient number, since it is larger than the sum of its proper divisors (1901965007).

13100024113 is a wasteful number, since it uses less digits than its factorization.

13100024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 651228.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13100024113 its reverse (31142000131), we get a palindrome (44242024244).

The spelling of 13100024113 in words is "thirteen billion, one hundred million, twenty-four thousand, one hundred thirteen".

Divisors: 1 11 31 59 341 649 1829 20119 651127 7162397 20184937 38416493 222034307 422581423 1190911283 13100024113