13100031210041 has 4 divisors (see below), whose sum is σ = 13100193594612. Its totient is φ = 13099868825472.

The previous prime is 13100031210023. The next prime is 13100031210067. The reversal of 13100031210041 is 14001213000131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2269376538025 + 10830654672016 = 1506445^2 + 3290996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100031210041 is a prime.

It is a super-2 number, since 2×13100031210041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100031213041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81071216 + ... + 81232641.

It is an arithmetic number, because the mean of its divisors is an integer number (3275048398653).

Almost surely, 2^{13100031210041} is an apocalyptic number.

It is an amenable number.

13100031210041 is a deficient number, since it is larger than the sum of its proper divisors (162384571).

13100031210041 is an equidigital number, since it uses as much as digits as its factorization.

13100031210041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162384570.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13100031210041 its reverse (14001213000131), we get a palindrome (27101244210172).

The spelling of 13100031210041 in words is "thirteen trillion, one hundred billion, thirty-one million, two hundred ten thousand, forty-one".