13100100403 has 12 divisors (see below), whose sum is σ = 14189369088. Its totient is φ = 12088945440.

The previous prime is 13100100401. The next prime is 13100100439. The reversal of 13100100403 is 30400100131.

It is not a de Polignac number, because 13100100403 - 2¹ = 13100100401 is a prime.

It is a super-2 number, since 2×13100100403² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100100401) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 727438 + ... + 745228.

It is an arithmetic number, because the mean of its divisors is an integer number (1182447424).

Almost surely, 2^13100100403 is an apocalyptic number.

13100100403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13100100403 is a deficient number, since it is larger than the sum of its proper divisors (1089268685).

13100100403 is a wasteful number, since it uses less digits than its factorization.

13100100403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22174 (or 22161 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13100100403 its reverse (30400100131), we get a palindrome (43500200534).

The spelling of 13100100403 in words is "thirteen billion, one hundred million, one hundred thousand, four hundred three".