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131001022451 = 132775153979
BaseRepresentation
bin111101000000001000…
…1001111011111110011
3110112010200112110021102
41322000101033133303
54121242230204301
6140103034315015
712315220214105
oct1720021173763
9415120473242
10131001022451
1150614731112
122147bb88a6b
13c4793ac200
1464aa401575
15361ab97b6b
hex1e8044f7f3

131001022451 has 6 divisors (see below), whose sum is σ = 141853178340. Its totient is φ = 120924020568.

The previous prime is 131001022417. The next prime is 131001022463. The reversal of 131001022451 is 154220100131.

It is not a de Polignac number, because 131001022451 - 222 = 130996828147 is a prime.

It is a super-2 number, since 2×1310010224512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131001022151) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 387576821 + ... + 387577158.

It is an arithmetic number, because the mean of its divisors is an integer number (23642196390).

Almost surely, 2131001022451 is an apocalyptic number.

131001022451 is a deficient number, since it is larger than the sum of its proper divisors (10852155889).

131001022451 is an equidigital number, since it uses as much as digits as its factorization.

131001022451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 775154005 (or 775153992 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 131001022451 its reverse (154220100131), we get a palindrome (285221122582).

The spelling of 131001022451 in words is "one hundred thirty-one billion, one million, twenty-two thousand, four hundred fifty-one".

Divisors: 1 13 169 775153979 10077001727 131001022451