Base | Representation |
---|---|
bin | 10011000100000010101… |
… | …100110000011001110001 |
3 | 11122020100212112000011202 |
4 | 103010002230300121301 |
5 | 132430400114443210 |
6 | 2441451015220545 |
7 | 163434163633352 |
oct | 23040254603161 |
9 | 4566325460152 |
10 | 1310010312305 |
11 | 46563273aa72 |
12 | 191a7b977755 |
13 | 966c1c85666 |
14 | 47594c33d29 |
15 | 24122b6d9a5 |
hex | 13102b30671 |
1310010312305 has 8 divisors (see below), whose sum is σ = 1572128241192. Its totient is φ = 1047931005568.
The previous prime is 1310010312187. The next prime is 1310010312313. The reversal of 1310010312305 is 5032130100131.
It can be written as a sum of positive squares in 4 ways, for example, as 725329865569 + 584680446736 = 851663^2 + 764644^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1310010312305 - 214 = 1310010295921 is a prime.
It is a super-2 number, since 2×13100103123052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9580862 + ... + 9716631.
It is an arithmetic number, because the mean of its divisors is an integer number (196516030149).
Almost surely, 21310010312305 is an apocalyptic number.
It is an amenable number.
1310010312305 is a deficient number, since it is larger than the sum of its proper divisors (262117928887).
1310010312305 is a wasteful number, since it uses less digits than its factorization.
1310010312305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19311075.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 1310010312305 its reverse (5032130100131), we get a palindrome (6342140412436).
The spelling of 1310010312305 in words is "one trillion, three hundred ten billion, ten million, three hundred twelve thousand, three hundred five".
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