131001033341441 has 4 divisors (see below), whose sum is σ = 131049570222000. Its totient is φ = 130952496460884.

The previous prime is 131001033341389. The next prime is 131001033341483. The reversal of 131001033341441 is 144143330100131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131001033341441 - 2³⁴ = 130983853472257 is a prime.

It is a super-2 number, since 2×131001033341441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131001033341741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24268436231 + ... + 24268441628.

It is an arithmetic number, because the mean of its divisors is an integer number (32762392555500).

Almost surely, 2^{131001033341441} is an apocalyptic number.

It is an amenable number.

131001033341441 is a deficient number, since it is larger than the sum of its proper divisors (48536880559).

131001033341441 is an equidigital number, since it uses as much as digits as its factorization.

131001033341441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48536880558.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131001033341441 its reverse (144143330100131), we get a palindrome (275144363441572).

The spelling of 131001033341441 in words is "one hundred thirty-one trillion, one billion, thirty-three million, three hundred forty-one thousand, four hundred forty-one".