Base | Representation |
---|---|
bin | 11101110010010100010010… |
… | …101111110100010010010001 |
3 | 122011211120202201220012001222 |
4 | 131302110102233310102101 |
5 | 114132310234134120423 |
6 | 1142341025142534425 |
7 | 36410342451365606 |
oct | 3562242257642221 |
9 | 564746681805058 |
10 | 131001112020113 |
11 | 388172945a8305 |
12 | 12838a87437415 |
13 | 581347604c89a |
14 | 244c6b81926ad |
15 | 102298d76c3c8 |
hex | 772512bf4491 |
131001112020113 has 8 divisors (see below), whose sum is σ = 138707211386880. Its totient is φ = 123295029497920.
The previous prime is 131001112020071. The next prime is 131001112020131. The reversal of 131001112020113 is 311020211100131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131001112020113 - 216 = 131001111954577 is a prime.
It is a super-2 number, since 2×1310011120201132 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a junction number, because it is equal to n+sod(n) for n = 131001112020091 and 131001112020100.
It is not an unprimeable number, because it can be changed into a prime (131001112020413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14067248 + ... + 21445038.
It is an arithmetic number, because the mean of its divisors is an integer number (17338401423360).
Almost surely, 2131001112020113 is an apocalyptic number.
It is an amenable number.
131001112020113 is a deficient number, since it is larger than the sum of its proper divisors (7706099366767).
131001112020113 is a wasteful number, since it uses less digits than its factorization.
131001112020113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8422287.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 131001112020113 its reverse (311020211100131), we get a palindrome (442021323120244).
The spelling of 131001112020113 in words is "one hundred thirty-one trillion, one billion, one hundred twelve million, twenty thousand, one hundred thirteen".
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