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1310011201331 = 7223983583947
BaseRepresentation
bin10011000100000010110…
…000001001011100110011
311122020100221012011200122
4103010002300021130303
5132430400331420311
62441451050240455
7163434204325310
oct23040260113463
94566327164618
101310011201331
114656331979a8
12191a8012612b
13966c2207201
1447594dc5d07
1524122c970db
hex13102c09733

1310011201331 has 8 divisors (see below), whose sum is σ = 1497824348160. Its totient is φ = 1122365226888.

The previous prime is 1310011201307. The next prime is 1310011201403. The reversal of 1310011201331 is 1331021100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310011201331 is a prime.

It is a super-2 number, since 2×13100112013312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1310011203331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41776301 + ... + 41807646.

It is an arithmetic number, because the mean of its divisors is an integer number (187228043520).

Almost surely, 21310011201331 is an apocalyptic number.

1310011201331 is a deficient number, since it is larger than the sum of its proper divisors (187813146829).

1310011201331 is an equidigital number, since it uses as much as digits as its factorization.

1310011201331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83586193.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1310011201331 its reverse (1331021100131), we get a palindrome (2641032301462).

The spelling of 1310011201331 in words is "one trillion, three hundred ten billion, eleven million, two hundred one thousand, three hundred thirty-one".

Divisors: 1 7 2239 15673 83583947 585087629 187144457333 1310011201331