13100113123 has 4 divisors (see below), whose sum is σ = 13100565688. Its totient is φ = 13099660560.

The previous prime is 13100113109. The next prime is 13100113129. The reversal of 13100113123 is 32131100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100113123 is a prime.

It is a super-2 number, since 2×13100113123² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13100113097 and 13100113106.

It is not an unprimeable number, because it can be changed into a prime (13100113129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179661 + ... + 241822.

It is an arithmetic number, because the mean of its divisors is an integer number (3275141422).

Almost surely, 2^13100113123 is an apocalyptic number.

13100113123 is a deficient number, since it is larger than the sum of its proper divisors (452565).

13100113123 is an equidigital number, since it uses as much as digits as its factorization.

13100113123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452564.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13100113123 its reverse (32131100131), we get a palindrome (45231213254).

The spelling of 13100113123 in words is "thirteen billion, one hundred million, one hundred thirteen thousand, one hundred twenty-three".