13100113321 has 4 divisors (see below), whose sum is σ = 13322149200. Its totient is φ = 12878077444.

The previous prime is 13100113309. The next prime is 13100113333. The reversal of 13100113321 is 12331100131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13100113309) and next prime (13100113333).

It is a cyclic number.

It is not a de Polignac number, because 13100113321 - 2⁷ = 13100113193 is a prime.

It is a super-2 number, since 2×13100113321² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13100113295 and 13100113304.

It is not an unprimeable number, because it can be changed into a prime (13100110321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111017851 + ... + 111017968.

It is an arithmetic number, because the mean of its divisors is an integer number (3330537300).

Almost surely, 2^13100113321 is an apocalyptic number.

It is an amenable number.

13100113321 is a deficient number, since it is larger than the sum of its proper divisors (222035879).

13100113321 is an equidigital number, since it uses as much as digits as its factorization.

13100113321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222035878.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13100113321 its reverse (12331100131), we get a palindrome (25431213452).

The spelling of 13100113321 in words is "thirteen billion, one hundred million, one hundred thirteen thousand, three hundred twenty-one".