Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0100100001111000011001 |
3 | 1201101100200222012120200121 |
4 | 2332220130010201320121 |
5 | 3204113022011432301 |
6 | 43510040153233241 |
7 | 2521311133646155 |
oct | 276503404417031 |
9 | 51340628176617 |
10 | 13100121202201 |
11 | 41a0803998900 |
12 | 1576a84102821 |
13 | 74044a623027 |
14 | 3340991d6065 |
15 | 17ab6e3633a1 |
hex | bea1c121e19 |
13100121202201 has 12 divisors (see below), whose sum is σ = 14494666443712. Its totient is φ = 11830332195000.
The previous prime is 13100121202177. The next prime is 13100121202237. The reversal of 13100121202201 is 10220212100131.
It is not a de Polignac number, because 13100121202201 - 213 = 13100121194009 is a prime.
It is a super-2 number, since 2×131001212022012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13100121202271) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 358476645 + ... + 358513186.
Almost surely, 213100121202201 is an apocalyptic number.
13100121202201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13100121202201 is a deficient number, since it is larger than the sum of its proper divisors (1394545241511).
13100121202201 is a wasteful number, since it uses less digits than its factorization.
13100121202201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 716990004 (or 716989993 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13100121202201 its reverse (10220212100131), we get a palindrome (23320333302332).
The spelling of 13100121202201 in words is "thirteen trillion, one hundred billion, one hundred twenty-one million, two hundred two thousand, two hundred one".
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