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1310012232121 = 431187254910069
BaseRepresentation
bin10011000100000010110…
…100000101000110111001
311122020101000010112200001
4103010002310011012321
5132430401112411441
62441451124313001
7163434216150445
oct23040264050671
94566330115601
101310012232121
1146563383139a
12191a80542761
13966c24a8448
14475951b3825
1524122dec731
hex13102d051b9

1310012232121 has 16 divisors (see below), whose sum is σ = 1342266552000. Its totient is φ = 1277840386368.

The previous prime is 1310012232059. The next prime is 1310012232163. The reversal of 1310012232121 is 1212322100131.

It is a cyclic number.

It is not a de Polignac number, because 1310012232121 - 219 = 1310011707833 is a prime.

It is a super-2 number, since 2×13100122321212 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310012232181) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130098475 + ... + 130108543.

It is an arithmetic number, because the mean of its divisors is an integer number (83891659500).

Almost surely, 21310012232121 is an apocalyptic number.

It is an amenable number.

1310012232121 is a deficient number, since it is larger than the sum of its proper divisors (32254319879).

1310012232121 is a wasteful number, since it uses less digits than its factorization.

1310012232121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13848.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1310012232121 its reverse (1212322100131), we get a palindrome (2522334332252).

The spelling of 1310012232121 in words is "one trillion, three hundred ten billion, twelve million, two hundred thirty-two thousand, one hundred twenty-one".

Divisors: 1 43 1187 2549 10069 51041 109607 432967 3025663 11951903 25665881 130103509 513931829 1103632883 30465400747 1310012232121