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131001330003 = 343667110001
BaseRepresentation
bin111101000000001001…
…0011010100101010011
3110112010201010002011020
41322000102122211103
54121242320030003
6140103045050523
712315222634545
oct1720022324523
9415121102136
10131001330003
1150614921195
12214800b6a43
13c4794891ab
1464aa481695
15361ac08d53
hex1e8049a953

131001330003 has 4 divisors (see below), whose sum is σ = 174668440008. Its totient is φ = 87334220000.

The previous prime is 131001330001. The next prime is 131001330011. The reversal of 131001330003 is 300033100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131001330003 - 21 = 131001330001 is a prime.

It is a super-2 number, since 2×1310013300032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131001330001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21833554998 + ... + 21833555003.

It is an arithmetic number, because the mean of its divisors is an integer number (43667110002).

Almost surely, 2131001330003 is an apocalyptic number.

131001330003 is a deficient number, since it is larger than the sum of its proper divisors (43667110005).

131001330003 is an equidigital number, since it uses as much as digits as its factorization.

131001330003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43667110004.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 131001330003 its reverse (300033100131), we get a palindrome (431034430134).

The spelling of 131001330003 in words is "one hundred thirty-one billion, one million, three hundred thirty thousand, three".

Divisors: 1 3 43667110001 131001330003