13100141212433 has 8 divisors (see below), whose sum is σ = 14293104513696. Its totient is φ = 11907518140000.

The previous prime is 13100141212421. The next prime is 13100141212547. The reversal of 13100141212433 is 33421214100131.

13100141212433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100141212433 is a prime.

It is a super-2 number, since 2×13100141212433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100149212433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84976691 + ... + 85130712.

It is an arithmetic number, because the mean of its divisors is an integer number (1786638064212).

Almost surely, 2^{13100141212433} is an apocalyptic number.

It is an amenable number.

13100141212433 is a deficient number, since it is larger than the sum of its proper divisors (1192963301263).

13100141212433 is a wasteful number, since it uses less digits than its factorization.

13100141212433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 170114415.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13100141212433 its reverse (33421214100131), we get a palindrome (46521355312564).

The spelling of 13100141212433 in words is "thirteen trillion, one hundred billion, one hundred forty-one million, two hundred twelve thousand, four hundred thirty-three".