1310014131 has 4 divisors (see below), whose sum is σ = 1746685512. Its totient is φ = 873342752.

The previous prime is 1310014117. The next prime is 1310014133. The reversal of 1310014131 is 1314100131.

1310014131 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1314100131 = 3 ⋅438033377.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310014131 is a prime.

It is a super-2 number, since 2×1310014131² = 3432274046839370322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310014131.

It is not an unprimeable number, because it can be changed into a prime (1310014133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218335686 + ... + 218335691.

It is an arithmetic number, because the mean of its divisors is an integer number (436671378).

Almost surely, 2^1310014131 is an apocalyptic number.

1310014131 is a deficient number, since it is larger than the sum of its proper divisors (436671381).

1310014131 is an equidigital number, since it uses as much as digits as its factorization.

1310014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436671380.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 1310014131 is about 36194.1173535148. The cubic root of 1310014131 is about 1094.1881156793.

Adding to 1310014131 its reverse (1314100131), we get a palindrome (2624114262).

The spelling of 1310014131 in words is "one billion, three hundred ten million, fourteen thousand, one hundred thirty-one".