Base | Representation |
---|---|
bin | 1011111010100001110111… |
… | …0010110101111101110001 |
3 | 1201101100202222121202212111 |
4 | 2332220131302311331301 |
5 | 3204113101412322210 |
6 | 43510043105125321 |
7 | 2521311634520413 |
oct | 276503562657561 |
9 | 51340688552774 |
10 | 13100150120305 |
11 | 41a081924a466 |
12 | 1576a91929841 |
13 | 740453609731 |
14 | 33409cda29b3 |
15 | 17ab71b7688a |
hex | bea1dcb5f71 |
13100150120305 has 16 divisors (see below), whose sum is σ = 15777543709440. Its totient is φ = 10441944995328.
The previous prime is 13100150120273. The next prime is 13100150120417. The reversal of 13100150120305 is 50302105100131.
It is a cyclic number.
It is not a de Polignac number, because 13100150120305 - 25 = 13100150120273 is a prime.
It is a super-2 number, since 2×131001501203052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2646175 + ... + 5762164.
It is an arithmetic number, because the mean of its divisors is an integer number (986096481840).
Almost surely, 213100150120305 is an apocalyptic number.
It is an amenable number.
13100150120305 is a deficient number, since it is larger than the sum of its proper divisors (2677393589135).
13100150120305 is an equidigital number, since it uses as much as digits as its factorization.
13100150120305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8409480.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 13100150120305 its reverse (50302105100131), we get a palindrome (63402255220436).
The spelling of 13100150120305 in words is "thirteen trillion, one hundred billion, one hundred fifty million, one hundred twenty thousand, three hundred five".
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