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13100150120305 = 54636738408339
BaseRepresentation
bin1011111010100001110111…
…0010110101111101110001
31201101100202222121202212111
42332220131302311331301
53204113101412322210
643510043105125321
72521311634520413
oct276503562657561
951340688552774
1013100150120305
1141a081924a466
121576a91929841
13740453609731
1433409cda29b3
1517ab71b7688a
hexbea1dcb5f71

13100150120305 has 16 divisors (see below), whose sum is σ = 15777543709440. Its totient is φ = 10441944995328.

The previous prime is 13100150120273. The next prime is 13100150120417. The reversal of 13100150120305 is 50302105100131.

It is a cyclic number.

It is not a de Polignac number, because 13100150120305 - 25 = 13100150120273 is a prime.

It is a super-2 number, since 2×131001501203052 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2646175 + ... + 5762164.

It is an arithmetic number, because the mean of its divisors is an integer number (986096481840).

Almost surely, 213100150120305 is an apocalyptic number.

It is an amenable number.

13100150120305 is a deficient number, since it is larger than the sum of its proper divisors (2677393589135).

13100150120305 is an equidigital number, since it uses as much as digits as its factorization.

13100150120305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8409480.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 13100150120305 its reverse (50302105100131), we get a palindrome (63402255220436).

The spelling of 13100150120305 in words is "thirteen trillion, one hundred billion, one hundred fifty million, one hundred twenty thousand, three hundred five".

Divisors: 1 5 463 673 2315 3365 311599 1557995 8408339 42041695 3893060957 5658812147 19465304785 28294060735 2620030024061 13100150120305