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131002013121211 = 891471932731699
BaseRepresentation
bin11101110010010101001000…
…011101001111101010111011
3122011211200002112110212101201
4131302111020131033222323
5114132314110324334321
61142341254412355031
736410404002541531
oct3562251035175273
9564750075425351
10131002013121211
1138817707211961
1212839099175a77
13581358a9404bb
14244c761b18151
1510229e2915291
hex77254874fabb

131002013121211 has 4 divisors (see below), whose sum is σ = 132473945853000. Its totient is φ = 129530080389424.

The previous prime is 131002013121209. The next prime is 131002013121227. The reversal of 131002013121211 is 112121310200131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131002013121211 - 21 = 131002013121209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131002013121011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 735966365761 + ... + 735966365938.

It is an arithmetic number, because the mean of its divisors is an integer number (33118486463250).

Almost surely, 2131002013121211 is an apocalyptic number.

131002013121211 is a deficient number, since it is larger than the sum of its proper divisors (1471932731789).

131002013121211 is an equidigital number, since it uses as much as digits as its factorization.

131002013121211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1471932731788.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 131002013121211 its reverse (112121310200131), we get a palindrome (243123323321342).

The spelling of 131002013121211 in words is "one hundred thirty-one trillion, two billion, thirteen million, one hundred twenty-one thousand, two hundred eleven".

Divisors: 1 89 1471932731699 131002013121211