Base | Representation |
---|---|
bin | 11101110010010101001000… |
… | …011101001111101010111011 |
3 | 122011211200002112110212101201 |
4 | 131302111020131033222323 |
5 | 114132314110324334321 |
6 | 1142341254412355031 |
7 | 36410404002541531 |
oct | 3562251035175273 |
9 | 564750075425351 |
10 | 131002013121211 |
11 | 38817707211961 |
12 | 12839099175a77 |
13 | 581358a9404bb |
14 | 244c761b18151 |
15 | 10229e2915291 |
hex | 77254874fabb |
131002013121211 has 4 divisors (see below), whose sum is σ = 132473945853000. Its totient is φ = 129530080389424.
The previous prime is 131002013121209. The next prime is 131002013121227. The reversal of 131002013121211 is 112121310200131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131002013121211 - 21 = 131002013121209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131002013121011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 735966365761 + ... + 735966365938.
It is an arithmetic number, because the mean of its divisors is an integer number (33118486463250).
Almost surely, 2131002013121211 is an apocalyptic number.
131002013121211 is a deficient number, since it is larger than the sum of its proper divisors (1471932731789).
131002013121211 is an equidigital number, since it uses as much as digits as its factorization.
131002013121211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1471932731788.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 131002013121211 its reverse (112121310200131), we get a palindrome (243123323321342).
The spelling of 131002013121211 in words is "one hundred thirty-one trillion, two billion, thirteen million, one hundred twenty-one thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •