Search a number
-
+
1310020221203 = 3142258716813
BaseRepresentation
bin10011000100000011010…
…010100011100100010011
311122020101120011102121222
4103010003102203210103
5132430410134034303
62441452011435255
7163434344103311
oct23040322434423
94566346142558
101310020221203
11465638298741
12191a83155b2b
13966c4044905
14475962930b1
1524123979938
hex131034a3913

1310020221203 has 4 divisors (see below), whose sum is σ = 1352278938048. Its totient is φ = 1267761504360.

The previous prime is 1310020221199. The next prime is 1310020221241. The reversal of 1310020221203 is 3021220200131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310020221203 - 22 = 1310020221199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310020221403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21129358376 + ... + 21129358437.

It is an arithmetic number, because the mean of its divisors is an integer number (338069734512).

Almost surely, 21310020221203 is an apocalyptic number.

1310020221203 is a deficient number, since it is larger than the sum of its proper divisors (42258716845).

1310020221203 is an equidigital number, since it uses as much as digits as its factorization.

1310020221203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42258716844.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1310020221203 its reverse (3021220200131), we get a palindrome (4331240421334).

The spelling of 1310020221203 in words is "one trillion, three hundred ten billion, twenty million, two hundred twenty-one thousand, two hundred three".

Divisors: 1 31 42258716813 1310020221203