Base | Representation |
---|---|
bin | 11101110010010101001101… |
… | …101001100010111101000001 |
3 | 122011211200022121101112221021 |
4 | 131302111031221202331001 |
5 | 114132314300124411001 |
6 | 1142341311203425441 |
7 | 36410406111142045 |
oct | 3562251551427501 |
9 | 564750277345837 |
10 | 131002100232001 |
11 | 388177513aa549 |
12 | 12839102385281 |
13 | 58135a29c034b |
14 | 244c76d512025 |
15 | 10229ea3c0ba1 |
hex | 77254da62f41 |
131002100232001 has 8 divisors (see below), whose sum is σ = 131011657517664. Its totient is φ = 130992543306240.
The previous prime is 131002100231993. The next prime is 131002100232011. The reversal of 131002100232001 is 100232001200131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131002100232001 - 23 = 131002100231993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131002100232011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1461591750 + ... + 1461681376.
It is an arithmetic number, because the mean of its divisors is an integer number (16376457189708).
Almost surely, 2131002100232001 is an apocalyptic number.
It is an amenable number.
131002100232001 is a deficient number, since it is larger than the sum of its proper divisors (9557285663).
131002100232001 is an equidigital number, since it uses as much as digits as its factorization.
131002100232001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179951.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 131002100232001 its reverse (100232001200131), we get a palindrome (231234101432132).
The spelling of 131002100232001 in words is "one hundred thirty-one trillion, two billion, one hundred million, two hundred thirty-two thousand, one".
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