1310022131113 has 4 divisors (see below), whose sum is σ = 1352280909568. Its totient is φ = 1267763352660.

The previous prime is 1310022131111. The next prime is 1310022131129. The reversal of 1310022131113 is 3111312200131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310022131113 - 2¹ = 1310022131111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310022131111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21129389181 + ... + 21129389242.

It is an arithmetic number, because the mean of its divisors is an integer number (338070227392).

Almost surely, 2^{1310022131113} is an apocalyptic number.

It is an amenable number.

1310022131113 is a deficient number, since it is larger than the sum of its proper divisors (42258778455).

1310022131113 is an equidigital number, since it uses as much as digits as its factorization.

1310022131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42258778454.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1310022131113 its reverse (3111312200131), we get a palindrome (4421334331244).

The spelling of 1310022131113 in words is "one trillion, three hundred ten billion, twenty-two million, one hundred thirty-one thousand, one hundred thirteen".