131002333121 has 4 divisors (see below), whose sum is σ = 142911636144. Its totient is φ = 119093030100.

The previous prime is 131002333117. The next prime is 131002333123. The reversal of 131002333121 is 121333200131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131002333121 - 2² = 131002333117 is a prime.

It is a super-3 number, since 3×131002333121³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131002333093 and 131002333102.

It is not an unprimeable number, because it can be changed into a prime (131002333123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5954651495 + ... + 5954651516.

It is an arithmetic number, because the mean of its divisors is an integer number (35727909036).

Almost surely, 2^131002333121 is an apocalyptic number.

131002333121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131002333121 is a deficient number, since it is larger than the sum of its proper divisors (11909303023).

131002333121 is a wasteful number, since it uses less digits than its factorization.

131002333121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11909303022.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 131002333121 its reverse (121333200131), we get a palindrome (252335533252).

The spelling of 131002333121 in words is "one hundred thirty-one billion, two million, three hundred thirty-three thousand, one hundred twenty-one".