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1310030113201 = 1531855669571
BaseRepresentation
bin10011000100000011111…
…000010010100110110001
311122020102020202222220021
4103010003320102212301
5132430420202110301
62441453003443441
7163434524143045
oct23040370224661
94566366688807
101310030113201
11465642934747
12191a86526581
13966c60c9274
144759770a025
15241247808a1
hex13103e129b1

1310030113201 has 4 divisors (see below), whose sum is σ = 1310885784304. Its totient is φ = 1309174442100.

The previous prime is 1310030113193. The next prime is 1310030113211. The reversal of 1310030113201 is 1023110300131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310030113201 - 23 = 1310030113193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310030113211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427833255 + ... + 427836316.

It is an arithmetic number, because the mean of its divisors is an integer number (327721446076).

Almost surely, 21310030113201 is an apocalyptic number.

It is an amenable number.

1310030113201 is a deficient number, since it is larger than the sum of its proper divisors (855671103).

1310030113201 is an equidigital number, since it uses as much as digits as its factorization.

1310030113201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 855671102.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1310030113201 its reverse (1023110300131), we get a palindrome (2333140413332).

The spelling of 1310030113201 in words is "one trillion, three hundred ten billion, thirty million, one hundred thirteen thousand, two hundred one".

Divisors: 1 1531 855669571 1310030113201