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1310031113113 = 103139351726017
BaseRepresentation
bin10011000100000011111…
…100000110101110011001
311122020102022122210112001
4103010003330012232121
5132430420431104423
62441453041121001
7163434535506202
oct23040374065631
94566368583461
101310031113113
11465643457a18
12191a86929161
13966c6389428
14475978ca5a9
15241248cbcad
hex13103f06b99

1310031113113 has 16 divisors (see below), whose sum is σ = 1332696077440. Its totient is φ = 1287563475456.

The previous prime is 1310031113059. The next prime is 1310031113147. The reversal of 1310031113113 is 3113111300131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310031113113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310031113513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50339881 + ... + 50365897.

It is an arithmetic number, because the mean of its divisors is an integer number (83293504840).

Almost surely, 21310031113113 is an apocalyptic number.

It is an amenable number.

1310031113113 is a deficient number, since it is larger than the sum of its proper divisors (22664964327).

1310031113113 is a wasteful number, since it uses less digits than its factorization.

1310031113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29776.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1310031113113 its reverse (3113111300131), we get a palindrome (4423142413244).

The spelling of 1310031113113 in words is "one trillion, three hundred ten billion, thirty-one million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 103 139 3517 14317 26017 362251 488863 2679751 3616363 50352889 91501789 372485389 9424684267 12718748671 1310031113113