13100322241233 has 12 divisors (see below), whose sum is σ = 18926477590020. Its totient is φ = 8731798972416.

The previous prime is 13100322241231. The next prime is 13100322241241. The reversal of 13100322241233 is 33214222300131.

13100322241233 is a `hidden beast` number, since 1 + 3 + 100 + 322 + 2 + 4 + 1 + 233 = 666.

13100322241233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 4725132545169 + 8375189696064 = 2173737^2 + 2893992^2 .

It is not a de Polignac number, because 13100322241233 - 2¹ = 13100322241231 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13100322241197 and 13100322241206.

It is not an unprimeable number, because it can be changed into a prime (13100322241231) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 145718268 + ... + 145808141.

It is an arithmetic number, because the mean of its divisors is an integer number (1577206465835).

Almost surely, 2^{13100322241233} is an apocalyptic number.

It is an amenable number.

13100322241233 is a deficient number, since it is larger than the sum of its proper divisors (5826155348787).

13100322241233 is a wasteful number, since it uses less digits than its factorization.

13100322241233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 291531408 (or 291531405 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13100322241233 its reverse (33214222300131), we get a palindrome (46314544541364).

The spelling of 13100322241233 in words is "thirteen trillion, one hundred billion, three hundred twenty-two million, two hundred forty-one thousand, two hundred thirty-three".