Base | Representation |
---|---|
bin | 11101110010010110010000… |
… | …111111010011101101011011 |
3 | 122011211210020100021020021101 |
4 | 131302112100333103231123 |
5 | 114132324103340311303 |
6 | 1142342015242452231 |
7 | 36410446110121045 |
oct | 3562262077235533 |
9 | 564753210236241 |
10 | 131003230010203 |
11 | 38818181103641 |
12 | 12839378804077 |
13 | 5813722a99065 |
14 | 244c8395a2a95 |
15 | 1022a64689d1d |
hex | 772590fd3b5b |
131003230010203 has 4 divisors (see below), whose sum is σ = 131003340564600. Its totient is φ = 131003119455808.
The previous prime is 131003230010137. The next prime is 131003230010239. The reversal of 131003230010203 is 302010032300131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131003230010203 - 217 = 131003229879131 is a prime.
It is a super-2 number, since 2×1310032300102032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131003230010273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53480278 + ... + 55876171.
It is an arithmetic number, because the mean of its divisors is an integer number (32750835141150).
Almost surely, 2131003230010203 is an apocalyptic number.
131003230010203 is a deficient number, since it is larger than the sum of its proper divisors (110554397).
131003230010203 is a wasteful number, since it uses less digits than its factorization.
131003230010203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110554396.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 131003230010203 its reverse (302010032300131), we get a palindrome (433013262310334).
The spelling of 131003230010203 in words is "one hundred thirty-one trillion, three billion, two hundred thirty million, ten thousand, two hundred three".
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